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0=6x^2+18x-168
We move all terms to the left:
0-(6x^2+18x-168)=0
We add all the numbers together, and all the variables
-(6x^2+18x-168)=0
We get rid of parentheses
-6x^2-18x+168=0
a = -6; b = -18; c = +168;
Δ = b2-4ac
Δ = -182-4·(-6)·168
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-66}{2*-6}=\frac{-48}{-12} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+66}{2*-6}=\frac{84}{-12} =-7 $
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